Base | Representation |
---|---|
bin | 1010000000010110010101… |
… | …0000100111101111101011 |
3 | 1102221200210021111122120012 |
4 | 2200011211100213233223 |
5 | 2420220233141212341 |
6 | 35221501252522135 |
7 | 2213542522656314 |
oct | 240054520475753 |
9 | 42850707448505 |
10 | 11001110100971 |
11 | 35615a9943231 |
12 | 129810962034b |
13 | 61a528400533 |
14 | 2a0656b8360b |
15 | 14126dd880eb |
hex | a0165427beb |
11001110100971 has 2 divisors, whose sum is σ = 11001110100972. Its totient is φ = 11001110100970.
The previous prime is 11001110100947. The next prime is 11001110101031. The reversal of 11001110100971 is 17900101110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001110100971 - 234 = 10983930231787 is a prime.
It is a super-4 number, since 4×110011101009714 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (11001110109971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555050485 + 5500555050486.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555050486).
Almost surely, 211001110100971 is an apocalyptic number.
11001110100971 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001110100971 is an equidigital number, since it uses as much as digits as its factorization.
11001110100971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63, while the sum is 23.
Adding to 11001110100971 its reverse (17900101110011), we get a palindrome (28901211210982).
The spelling of 11001110100971 in words is "eleven trillion, one billion, one hundred ten million, one hundred thousand, nine hundred seventy-one".
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