11001300323 has 8 divisors (see below), whose sum is σ = 11962580448. Its totient is φ = 10056452544.

The previous prime is 11001300319. The next prime is 11001300379. The reversal of 11001300323 is 32300310011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11001300323 - 2² = 11001300319 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001300298 and 11001300307.

It is not an unprimeable number, because it can be changed into a prime (11001300313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4106690 + ... + 4109367.

It is an arithmetic number, because the mean of its divisors is an integer number (1495322556).

Almost surely, 2^11001300323 is an apocalyptic number.

11001300323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11001300323 is a deficient number, since it is larger than the sum of its proper divisors (961280125).

11001300323 is a wasteful number, since it uses less digits than its factorization.

11001300323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8216173.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 11001300323 its reverse (32300310011), we get a palindrome (43301610334).

The spelling of 11001300323 in words is "eleven billion, one million, three hundred thousand, three hundred twenty-three".