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1100201303330 = 25412683417813
BaseRepresentation
bin10000000000101001000…
…110111001110100100010
310220011210220212000222122
4100000221012321310202
5121011203013201310
62201231524104242
7142326004530503
oct20005106716442
93804726760878
101100201303330
11394657a54188
12159287235082
137c9966ca87c
143b370108baa
151d9434b6555
hex100291b9d22

1100201303330 has 16 divisors (see below), whose sum is σ = 2028663867384. Its totient is φ = 429346849920.

The previous prime is 1100201303309. The next prime is 1100201303339. The reversal of 1100201303330 is 333031020011.

It can be written as a sum of positive squares in 4 ways, for example, as 801889803289 + 298311500041 = 895483^2 + 546179^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1100201303299 and 1100201303308.

It is not an unprimeable number, because it can be changed into a prime (1100201303339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1341708497 + ... + 1341709316.

Almost surely, 21100201303330 is an apocalyptic number.

1100201303330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1100201303330 is a deficient number, since it is larger than the sum of its proper divisors (928462564054).

1100201303330 is a wasteful number, since it uses less digits than its factorization.

1100201303330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2683417861.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 1100201303330 its reverse (333031020011), we get a palindrome (1433232323341).

The spelling of 1100201303330 in words is "one trillion, one hundred billion, two hundred one million, three hundred three thousand, three hundred thirty".

Divisors: 1 2 5 10 41 82 205 410 2683417813 5366835626 13417089065 26834178130 110020130333 220040260666 550100651665 1100201303330