Base | Representation |
---|---|
bin | 1010000000101010001111… |
… | …0010101111111011110111 |
3 | 1102222012120201101010010202 |
4 | 2200022203302233323313 |
5 | 2420312204233431403 |
6 | 35224143435311115 |
7 | 2214122124042143 |
oct | 240124362577367 |
9 | 42865521333122 |
10 | 11006454202103 |
11 | 35638a1506538 |
12 | 129915b2ab49b |
13 | 61ab9a62b359 |
14 | 2a0a02818223 |
15 | 141483110688 |
hex | a02a3cafef7 |
11006454202103 has 8 divisors (see below), whose sum is σ = 11062546442640. Its totient is φ = 10950364203520.
The previous prime is 11006454202097. The next prime is 11006454202123. The reversal of 11006454202103 is 30120245460011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11006454202103 - 24 = 11006454202087 is a prime.
It is a super-2 number, since 2×110064542021032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11006454202123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9766688 + ... + 10835178.
It is an arithmetic number, because the mean of its divisors is an integer number (1382818305330).
Almost surely, 211006454202103 is an apocalyptic number.
11006454202103 is a deficient number, since it is larger than the sum of its proper divisors (56092240537).
11006454202103 is a wasteful number, since it uses less digits than its factorization.
11006454202103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1120977.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 11006454202103 its reverse (30120245460011), we get a palindrome (41126699662114).
The spelling of 11006454202103 in words is "eleven trillion, six billion, four hundred fifty-four million, two hundred two thousand, one hundred three".
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