Base | Representation |
---|---|
bin | 1010000000111011001101… |
… | …1001111110010011000011 |
3 | 1102222122100022000000201101 |
4 | 2200032303121332103003 |
5 | 2420401022321010313 |
6 | 35230215541515231 |
7 | 2214343056111145 |
oct | 240166331762303 |
9 | 42878308000641 |
10 | 11011011110083 |
11 | 356581a795996 |
12 | 129a011412b17 |
13 | 61b44573b5ca |
14 | 2a0d15ad8c95 |
15 | 14164d1e05dd |
hex | a03b367e4c3 |
11011011110083 has 2 divisors, whose sum is σ = 11011011110084. Its totient is φ = 11011011110082.
The previous prime is 11011011109981. The next prime is 11011011110117. The reversal of 11011011110083 is 38001111011011.
11011011110083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11011011110083 - 225 = 11010977555651 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11011011110083.
It is not a weakly prime, because it can be changed into another prime (11011711110083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505505555041 + 5505505555042.
It is an arithmetic number, because the mean of its divisors is an integer number (5505505555042).
Almost surely, 211011011110083 is an apocalyptic number.
11011011110083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011011110083 is an equidigital number, since it uses as much as digits as its factorization.
11011011110083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 19.
Adding to 11011011110083 its reverse (38001111011011), we get a palindrome (49012122121094).
The spelling of 11011011110083 in words is "eleven trillion, eleven billion, eleven million, one hundred ten thousand, eighty-three".
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