11033000103 has 4 divisors (see below), whose sum is σ = 14710666808. Its totient is φ = 7355333400.

The previous prime is 11033000053. The next prime is 11033000117. The reversal of 11033000103 is 30100033011.

11033000103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11033000103 - 2²⁵ = 10999445671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11033000183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838833348 + ... + 1838833353.

It is an arithmetic number, because the mean of its divisors is an integer number (3677666702).

Almost surely, 2^11033000103 is an apocalyptic number.

11033000103 is a deficient number, since it is larger than the sum of its proper divisors (3677666705).

11033000103 is an equidigital number, since it uses as much as digits as its factorization.

11033000103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3677666704.

The product of its (nonzero) digits is 27, while the sum is 12.

Adding to 11033000103 its reverse (30100033011), we get a palindrome (41133033114).

The spelling of 11033000103 in words is "eleven billion, thirty-three million, one hundred three", and thus it is an aban number.