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11033000105 = 512703173707
BaseRepresentation
bin10100100011001111…
…00011100010101001
31001110220112110212112
422101213203202221
5140043422000410
65022443252105
7540256645031
oct122147434251
931426473775
1011033000105
114751928306
12217ab1a035
13106aa1003a
147694208c1
1544890c105
hex2919e38a9

11033000105 has 8 divisors (see below), whose sum is σ = 13240718592. Its totient is φ = 8825654448.

The previous prime is 11033000053. The next prime is 11033000117. The reversal of 11033000105 is 50100033011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11033000105 - 28 = 11032999849 is a prime.

It is a super-2 number, since 2×110330001052 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11033000105.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23339 + ... + 150368.

It is an arithmetic number, because the mean of its divisors is an integer number (1655089824).

Almost surely, 211033000105 is an apocalyptic number.

It is an amenable number.

11033000105 is a deficient number, since it is larger than the sum of its proper divisors (2207718487).

11033000105 is a wasteful number, since it uses less digits than its factorization.

11033000105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 186415.

The product of its (nonzero) digits is 45, while the sum is 14.

Adding to 11033000105 its reverse (50100033011), we get a palindrome (61133033116).

The spelling of 11033000105 in words is "eleven billion, thirty-three million, one hundred five", and thus it is an aban number.

Divisors: 1 5 12703 63515 173707 868535 2206600021 11033000105