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11043341 is a prime number
BaseRepresentation
bin101010001000…
…001000001101
3202210001121122
4222020020031
510311341331
61032410325
7162603221
oct52101015
922701548
1011043341
116263031
1238469a5
13239872a
141676781
15e8217b
hexa8820d

11043341 has 2 divisors, whose sum is σ = 11043342. Its totient is φ = 11043340.

The previous prime is 11043337. The next prime is 11043359. The reversal of 11043341 is 14334011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9672100 + 1371241 = 3110^2 + 1171^2 .

It is an emirp because it is prime and its reverse (14334011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11043341 - 22 = 11043337 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11043371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521670 + 5521671.

It is an arithmetic number, because the mean of its divisors is an integer number (5521671).

Almost surely, 211043341 is an apocalyptic number.

It is an amenable number.

11043341 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043341 is an equidigital number, since it uses as much as digits as its factorization.

11043341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 11043341 is about 3323.1522685547. The cubic root of 11043341 is about 222.6897157327.

Adding to 11043341 its reverse (14334011), we get a palindrome (25377352).

The spelling of 11043341 in words is "eleven million, forty-three thousand, three hundred forty-one".