11100401401 has 4 divisors (see below), whose sum is σ = 11103961204. Its totient is φ = 11096841600.

The previous prime is 11100401393. The next prime is 11100401441. The reversal of 11100401401 is 10410400111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10410400111 = 359 ⋅28998329.

It can be written as a sum of positive squares in 2 ways, for example, as 5190482025 + 5909919376 = 72045^2 + 76876^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100401401 - 2³ = 11100401393 is a prime.

It is a super-3 number, since 3×11100401401³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11100401441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1775220 + ... + 1781461.

It is an arithmetic number, because the mean of its divisors is an integer number (2775990301).

Almost surely, 2^11100401401 is an apocalyptic number.

It is an amenable number.

11100401401 is a deficient number, since it is larger than the sum of its proper divisors (3559803).

11100401401 is an equidigital number, since it uses as much as digits as its factorization.

11100401401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3559802.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 11100401401 its reverse (10410400111), we get a palindrome (21510801512).

The spelling of 11100401401 in words is "eleven billion, one hundred million, four hundred one thousand, four hundred one".