Base | Representation |
---|---|
bin | 1010000110001010011111… |
… | …0000111000001110001101 |
3 | 1110022020122110222110211012 |
4 | 2201202213300320032031 |
5 | 2423334332041214013 |
6 | 35335422244335005 |
7 | 2224010243653151 |
oct | 241424760701615 |
9 | 43266573873735 |
10 | 11101010101133 |
11 | 359aa03887a37 |
12 | 12b35499a4465 |
13 | 626a89299574 |
14 | 2a5412813061 |
15 | 143b6941d1a8 |
hex | a18a7c3838d |
11101010101133 has 2 divisors, whose sum is σ = 11101010101134. Its totient is φ = 11101010101132.
The previous prime is 11101010101091. The next prime is 11101010101141. The reversal of 11101010101133 is 33110101010111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6598389225289 + 4502620875844 = 2568733^2 + 2121938^2 .
It is a cyclic number.
It is not a de Polignac number, because 11101010101133 - 210 = 11101010100109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11101010101163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550505050566 + 5550505050567.
It is an arithmetic number, because the mean of its divisors is an integer number (5550505050567).
Almost surely, 211101010101133 is an apocalyptic number.
It is an amenable number.
11101010101133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101010101133 is an equidigital number, since it uses as much as digits as its factorization.
11101010101133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 14.
Adding to 11101010101133 its reverse (33110101010111), we get a palindrome (44211111111244).
The spelling of 11101010101133 in words is "eleven trillion, one hundred one billion, ten million, one hundred one thousand, one hundred thirty-three".
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