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11101010101141 is a prime number
BaseRepresentation
bin1010000110001010011111…
…0000111000001110010101
31110022020122110222110211111
42201202213300320032111
52423334332041214031
635335422244335021
72224010243653162
oct241424760701625
943266573873744
1011101010101141
11359aa03887a44
1212b35499a4471
13626a8929957c
142a5412813069
15143b6941d1b1
hexa18a7c38395

11101010101141 has 2 divisors, whose sum is σ = 11101010101142. Its totient is φ = 11101010101140.

The previous prime is 11101010101133. The next prime is 11101010101163. The reversal of 11101010101141 is 14110101010111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5920510904100 + 5180499197041 = 2433210^2 + 2276071^2 .

It is a cyclic number.

It is not a de Polignac number, because 11101010101141 - 23 = 11101010101133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11101010101541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550505050570 + 5550505050571.

It is an arithmetic number, because the mean of its divisors is an integer number (5550505050571).

Almost surely, 211101010101141 is an apocalyptic number.

It is an amenable number.

11101010101141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101010101141 is an equidigital number, since it uses as much as digits as its factorization.

11101010101141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 11101010101141 its reverse (14110101010111), we get a palindrome (25211111111252).

The spelling of 11101010101141 in words is "eleven trillion, one hundred one billion, ten million, one hundred one thousand, one hundred forty-one".