Base | Representation |
---|---|
bin | 1010000110001110100101… |
… | …1001010001101000011011 |
3 | 1110022100111012220121020111 |
4 | 2201203221121101220123 |
5 | 2423344110432210021 |
6 | 35340123421105151 |
7 | 2224046444145133 |
oct | 241435131215033 |
9 | 43270435817214 |
10 | 11102111210011 |
11 | 35a041938a378 |
12 | 12b37b66b81b7 |
13 | 626c03447b93 |
14 | 2a54b8b5dac3 |
15 | 143bd0e228e1 |
hex | a18e9651a1b |
11102111210011 has 4 divisors (see below), whose sum is σ = 11102659185024. Its totient is φ = 11101563235000.
The previous prime is 11102111209997. The next prime is 11102111210023. The reversal of 11102111210011 is 11001211120111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11102111210011 - 219 = 11102110685723 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11102111209973 and 11102111210000.
It is not an unprimeable number, because it can be changed into a prime (11102111210081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273957115 + ... + 273997636.
It is an arithmetic number, because the mean of its divisors is an integer number (2775664796256).
Almost surely, 211102111210011 is an apocalyptic number.
11102111210011 is a deficient number, since it is larger than the sum of its proper divisors (547975013).
11102111210011 is an equidigital number, since it uses as much as digits as its factorization.
11102111210011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 547975012.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 11102111210011 its reverse (11001211120111), we get a palindrome (22103322330122).
The spelling of 11102111210011 in words is "eleven trillion, one hundred two billion, one hundred eleven million, two hundred ten thousand, eleven".
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