Base | Representation |
---|---|
bin | 10000001001111101110… |
… | …010110000011111101011 |
3 | 10221010122120210010220020 |
4 | 100021331302300133223 |
5 | 121142203234121303 |
6 | 2210005132331523 |
7 | 143132042316126 |
oct | 20117562603753 |
9 | 3833576703806 |
10 | 1110212020203 |
11 | 398924818a10 |
12 | 15b1bb913ba3 |
13 | 8090069ac90 |
14 | 3ba3d85b3bd |
15 | 1dd2c28ea53 |
hex | 1027dcb07eb |
1110212020203 has 32 divisors (see below), whose sum is σ = 1741620061440. Its totient is φ = 620188103040.
The previous prime is 1110212020189. The next prime is 1110212020241. The reversal of 1110212020203 is 3020202120111.
It is not a de Polignac number, because 1110212020203 - 29 = 1110212019691 is a prime.
It is a super-2 number, since 2×11102120202032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1110212020243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1601508 + ... + 2187521.
It is an arithmetic number, because the mean of its divisors is an integer number (54425626920).
Almost surely, 21110212020203 is an apocalyptic number.
1110212020203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1110212020203 is a deficient number, since it is larger than the sum of its proper divisors (631408041237).
1110212020203 is a wasteful number, since it uses less digits than its factorization.
1110212020203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3789739.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 1110212020203 its reverse (3020202120111), we get a palindrome (4130414140314).
The spelling of 1110212020203 in words is "one trillion, one hundred ten billion, two hundred twelve million, twenty thousand, two hundred three".
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