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111021457 is a prime number
BaseRepresentation
bin1101001111000…
…00110110010001
321201220110210211
412213200312101
5211410141312
615003324121
72515444501
oct647406621
9251813724
10111021457
115773a078
1231220641
131a002291
1410a5da01
159b303a7
hex69e0d91

111021457 has 2 divisors, whose sum is σ = 111021458. Its totient is φ = 111021456.

The previous prime is 111021439. The next prime is 111021461. The reversal of 111021457 is 754120111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111007296 + 14161 = 10536^2 + 119^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111021457 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (111021467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510728 + 55510729.

It is an arithmetic number, because the mean of its divisors is an integer number (55510729).

Almost surely, 2111021457 is an apocalyptic number.

It is an amenable number.

111021457 is a deficient number, since it is larger than the sum of its proper divisors (1).

111021457 is an equidigital number, since it uses as much as digits as its factorization.

111021457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 280, while the sum is 22.

The square root of 111021457 is about 10536.6720078021. The cubic root of 111021457 is about 480.6205183725.

Adding to 111021457 its reverse (754120111), we get a palindrome (865141568).

The spelling of 111021457 in words is "one hundred eleven million, twenty-one thousand, four hundred fifty-seven".