Base | Representation |
---|---|
bin | 10100101100011010… |
… | …11111111001001111 |
3 | 1001200021112022000011 |
4 | 22112031133321033 |
5 | 140223133234003 |
6 | 5034235014051 |
7 | 542213625241 |
oct | 122615377117 |
9 | 31607468004 |
10 | 11110055503 |
11 | 4791378158 |
12 | 21a089a327 |
13 | 108097c051 |
14 | 77575c091 |
15 | 45057d46d |
hex | 29635fe4f |
11110055503 has 2 divisors, whose sum is σ = 11110055504. Its totient is φ = 11110055502.
The previous prime is 11110055501. The next prime is 11110055513. The reversal of 11110055503 is 30555001111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11110055503 - 21 = 11110055501 is a prime.
Together with 11110055501, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11110055501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555027751 + 5555027752.
It is an arithmetic number, because the mean of its divisors is an integer number (5555027752).
Almost surely, 211110055503 is an apocalyptic number.
11110055503 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110055503 is an equidigital number, since it uses as much as digits as its factorization.
11110055503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 375, while the sum is 22.
Adding to 11110055503 its reverse (30555001111), we get a palindrome (41665056614).
The spelling of 11110055503 in words is "eleven billion, one hundred ten million, fifty-five thousand, five hundred three".
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