Base | Representation |
---|---|
bin | 11001010000111000001011… |
… | …101011111000011000011111 |
3 | 112120102002220122001110010101 |
4 | 121100320023223320120133 |
5 | 104030420312000000111 |
6 | 1032151404433321531 |
7 | 32255335105640203 |
oct | 3120701353703037 |
9 | 476362818043111 |
10 | 111111000000031 |
11 | 32448a01929aa9 |
12 | 105660811062a7 |
13 | 49cc950ca4095 |
14 | 1d61b302b8b03 |
15 | cca3bac52bc1 |
hex | 650e0baf861f |
111111000000031 has 2 divisors, whose sum is σ = 111111000000032. Its totient is φ = 111111000000030.
The previous prime is 111110999999977. The next prime is 111111000000059. The reversal of 111111000000031 is 130000000111111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111111000000031 - 211 = 111110999997983 is a prime.
It is a super-2 number, since 2×1111110000000312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111110999999954 and 111111000000017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111111000700031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555500000015 + 55555500000016.
It is an arithmetic number, because the mean of its divisors is an integer number (55555500000016).
Almost surely, 2111111000000031 is an apocalyptic number.
111111000000031 is a deficient number, since it is larger than the sum of its proper divisors (1).
111111000000031 is an equidigital number, since it uses as much as digits as its factorization.
111111000000031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 10.
Adding to 111111000000031 its reverse (130000000111111), we get a palindrome (241111000111142).
The spelling of 111111000000031 in words is "one hundred eleven trillion, one hundred eleven billion, thirty-one", and thus it is an aban number.
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