11113110221333 has 16 divisors (see below), whose sum is σ = 11466769198080. Its totient is φ = 10763951677920.

The previous prime is 11113110221327. The next prime is 11113110221347. The reversal of 11113110221333 is 33312201131111.

It is a de Polignac number, because none of the positive numbers 2^k-11113110221333 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11113110221299 and 11113110221308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11113710221333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 110059916 + ... + 110160842.

It is an arithmetic number, because the mean of its divisors is an integer number (716673074880).

Almost surely, 2^{11113110221333} is an apocalyptic number.

It is an amenable number.

11113110221333 is a deficient number, since it is larger than the sum of its proper divisors (353658976747).

11113110221333 is an frugal number, since it uses more digits than its factorization.

11113110221333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101385 (or 101107 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 11113110221333 its reverse (33312201131111), we get a palindrome (44425311352444).

The spelling of 11113110221333 in words is "eleven trillion, one hundred thirteen billion, one hundred ten million, two hundred twenty-one thousand, three hundred thirty-three".