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111200214103 = 1110109110373
BaseRepresentation
bin110011110010000001…
…1001001110001010111
3101122000201211011121021
41213210003021301113
53310214223322403
6123030142302011
711014434136636
oct1474403116127
9348021734537
10111200214103
11431836927a0
1219674887907
13a642067974
14554c76b51d
152d5c6768bd
hex19e40c9c57

111200214103 has 4 divisors (see below), whose sum is σ = 121309324488. Its totient is φ = 101091103720.

The previous prime is 111200214061. The next prime is 111200214127. The reversal of 111200214103 is 301412002111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111200214103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111200214133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5054555176 + ... + 5054555197.

It is an arithmetic number, because the mean of its divisors is an integer number (30327331122).

Almost surely, 2111200214103 is an apocalyptic number.

111200214103 is a deficient number, since it is larger than the sum of its proper divisors (10109110385).

111200214103 is a wasteful number, since it uses less digits than its factorization.

111200214103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10109110384.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 111200214103 its reverse (301412002111), we get a palindrome (412612216214).

The spelling of 111200214103 in words is "one hundred eleven billion, two hundred million, two hundred fourteen thousand, one hundred three".

Divisors: 1 11 10109110373 111200214103