1113050450353 has 4 divisors (see below), whose sum is σ = 1127139696640. Its totient is φ = 1098961204068.

The previous prime is 1113050450333. The next prime is 1113050450381. The reversal of 1113050450353 is 3530540503111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113050450353 - 2²¹ = 1113048353201 is a prime.

It is a super-2 number, since 2×1113050450353² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1113050450333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7044623025 + ... + 7044623182.

It is an arithmetic number, because the mean of its divisors is an integer number (281784924160).

Almost surely, 2^{1113050450353} is an apocalyptic number.

It is an amenable number.

1113050450353 is a deficient number, since it is larger than the sum of its proper divisors (14089246287).

1113050450353 is an equidigital number, since it uses as much as digits as its factorization.

1113050450353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14089246286.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 1113050450353 its reverse (3530540503111), we get a palindrome (4643590953464).

The spelling of 1113050450353 in words is "one trillion, one hundred thirteen billion, fifty million, four hundred fifty thousand, three hundred fifty-three".