Base | Representation |
---|---|
bin | 10100101110111011… |
… | …10110100111101111 |
3 | 1001201202011111012211 |
4 | 22113131312213233 |
5 | 140244031320421 |
6 | 5040310311251 |
7 | 542560650136 |
oct | 122735664757 |
9 | 31652144184 |
10 | 11131120111 |
11 | 47a2255321 |
12 | 21a7958527 |
13 | 1085145c07 |
14 | 77848291d |
15 | 45233e9e1 |
hex | 2977769ef |
11131120111 has 2 divisors, whose sum is σ = 11131120112. Its totient is φ = 11131120110.
The previous prime is 11131120097. The next prime is 11131120153. The reversal of 11131120111 is 11102113111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11131120111 - 25 = 11131120079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11131120091 and 11131120100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11131120171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565560055 + 5565560056.
It is an arithmetic number, because the mean of its divisors is an integer number (5565560056).
Almost surely, 211131120111 is an apocalyptic number.
11131120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131120111 is an equidigital number, since it uses as much as digits as its factorization.
11131120111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 11131120111 its reverse (11102113111), we get a palindrome (22233233222).
The spelling of 11131120111 in words is "eleven billion, one hundred thirty-one million, one hundred twenty thousand, one hundred eleven".
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