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11134477 is a prime number
BaseRepresentation
bin101010011110…
…011000001101
3202221200122001
4222132120031
510322300402
61034352301
7163433014
oct52363015
922850561
1011134477
116315552
12388b691
1323cb063
14169ba7b
15e9e187
hexa9e60d

11134477 has 2 divisors, whose sum is σ = 11134478. Its totient is φ = 11134476.

The previous prime is 11134469. The next prime is 11134481. The reversal of 11134477 is 77443111.

11134477 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9205156 + 1929321 = 3034^2 + 1389^2 .

It is an emirp because it is prime and its reverse (77443111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11134477 - 23 = 11134469 is a prime.

It is a Chen prime.

It is a plaindrome in base 10.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11134427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567238 + 5567239.

It is an arithmetic number, because the mean of its divisors is an integer number (5567239).

Almost surely, 211134477 is an apocalyptic number.

It is an amenable number.

11134477 is a deficient number, since it is larger than the sum of its proper divisors (1).

11134477 is an equidigital number, since it uses as much as digits as its factorization.

11134477 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2352, while the sum is 28.

The square root of 11134477 is about 3336.8363759705. The cubic root of 11134477 is about 223.3006261352.

Adding to 11134477 its reverse (77443111), we get a palindrome (88577588).

It can be divided in two parts, 11134 and 477, that added together give a palindrome (11611).

The spelling of 11134477 in words is "eleven million, one hundred thirty-four thousand, four hundred seventy-seven".