Base | Representation |
---|---|
bin | 10000001101100111100… |
… | …001011011000000101101 |
3 | 10221111202212110001022002 |
4 | 100031213201123000231 |
5 | 121223221114004201 |
6 | 2211454212102045 |
7 | 143331156112655 |
oct | 20154741330055 |
9 | 3844685401262 |
10 | 1114133344301 |
11 | 39a55725582a |
12 | 15bb15004925 |
13 | 810a6c03bb3 |
14 | 3bcd2571365 |
15 | 1deab67376b |
hex | 1036785b02d |
1114133344301 has 4 divisors (see below), whose sum is σ = 1162573924512. Its totient is φ = 1065692764092.
The previous prime is 1114133344271. The next prime is 1114133344343. The reversal of 1114133344301 is 1034433314111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1114133344301 - 214 = 1114133327917 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1114133344001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24220290071 + ... + 24220290116.
It is an arithmetic number, because the mean of its divisors is an integer number (290643481128).
Almost surely, 21114133344301 is an apocalyptic number.
It is an amenable number.
1114133344301 is a deficient number, since it is larger than the sum of its proper divisors (48440580211).
1114133344301 is an equidigital number, since it uses as much as digits as its factorization.
1114133344301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48440580210.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 1114133344301 its reverse (1034433314111), we get a palindrome (2148566658412).
The spelling of 1114133344301 in words is "one trillion, one hundred fourteen billion, one hundred thirty-three million, three hundred forty-four thousand, three hundred one".
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