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112002113 = 239946687
BaseRepresentation
bin1101010110100…
…00010001000001
321210202022000102
412223100101001
5212133031423
615040332145
72530000526
oct653202101
9253668012
10112002113
1158249933
1231614055
131a286752
1410c3714d
159c75c28
hex6ad0441

112002113 has 4 divisors (see below), whose sum is σ = 112051200. Its totient is φ = 111953028.

The previous prime is 112002067. The next prime is 112002151. The reversal of 112002113 is 311200211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112002113 - 214 = 111985729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112002094 and 112002103.

It is not an unprimeable number, because it can be changed into a prime (112002173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20945 + ... + 25742.

It is an arithmetic number, because the mean of its divisors is an integer number (28012800).

Almost surely, 2112002113 is an apocalyptic number.

It is an amenable number.

112002113 is a deficient number, since it is larger than the sum of its proper divisors (49087).

112002113 is an equidigital number, since it uses as much as digits as its factorization.

112002113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49086.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 112002113 is about 10583.1050736540. The cubic root of 112002113 is about 482.0314841437.

Adding to 112002113 its reverse (311200211), we get a palindrome (423202324).

It can be divided in two parts, 11200211 and 3, that multiplied together give a palindrome (33600633).

The spelling of 112002113 in words is "one hundred twelve million, two thousand, one hundred thirteen".

Divisors: 1 2399 46687 112002113