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11202310212 = 2235091834039
BaseRepresentation
bin10100110111011010…
…11011000001000100
31001220201010022200020
422123231123001010
5140420242411322
65051332215140
7544414031352
oct123355330104
931821108606
1011202310212
114829459515
12220776a4b0
131096b10332
14783ad47d2
1545870305c
hex29bb5b044

11202310212 has 24 divisors (see below), whose sum is σ = 26190091200. Its totient is φ = 3726765216.

The previous prime is 11202310201. The next prime is 11202310261. The reversal of 11202310212 is 21201320211.

It is a junction number, because it is equal to n+sod(n) for n = 11202310191 and 11202310200.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 910912 + ... + 923127.

It is an arithmetic number, because the mean of its divisors is an integer number (1091253800).

Almost surely, 211202310212 is an apocalyptic number.

11202310212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11202310212 is an abundant number, since it is smaller than the sum of its proper divisors (14987780988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11202310212 is a wasteful number, since it uses less digits than its factorization.

11202310212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1834555 (or 1834553 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11202310212 its reverse (21201320211), we get a palindrome (32403630423).

Subtracting 11202310212 from its reverse (21201320211), we obtain a palindrome (9999009999).

The spelling of 11202310212 in words is "eleven billion, two hundred two million, three hundred ten thousand, two hundred twelve".

Divisors: 1 2 3 4 6 12 509 1018 1527 2036 3054 6108 1834039 3668078 5502117 7336156 11004234 22008468 933525851 1867051702 2800577553 3734103404 5601155106 11202310212