Base | Representation |
---|---|
bin | 11001011111011100011100… |
… | …101010011101111010100001 |
3 | 112200221210200220011002021011 |
4 | 121133130130222131322201 |
5 | 104143320400112101423 |
6 | 1034235314123300521 |
7 | 32420553114303061 |
oct | 3137343452357241 |
9 | 480853626132234 |
10 | 112112012222113 |
11 | 327a448a166372 |
12 | 106a808607a741 |
13 | 4a7316ab98ba7 |
14 | 1d98370d313a1 |
15 | ce64562b1b0d |
hex | 65f71ca9dea1 |
112112012222113 has 2 divisors, whose sum is σ = 112112012222114. Its totient is φ = 112112012222112.
The previous prime is 112112012222087. The next prime is 112112012222267. The reversal of 112112012222113 is 311222210211211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107020928488464 + 5091083733649 = 10345092^2 + 2256343^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112112012222113 is a prime.
It is not a weakly prime, because it can be changed into another prime (112112012222813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056006111056 + 56056006111057.
It is an arithmetic number, because the mean of its divisors is an integer number (56056006111057).
Almost surely, 2112112012222113 is an apocalyptic number.
It is an amenable number.
112112012222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
112112012222113 is an equidigital number, since it uses as much as digits as its factorization.
112112012222113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 112112012222113 its reverse (311222210211211), we get a palindrome (423334222433324).
The spelling of 112112012222113 in words is "one hundred twelve trillion, one hundred twelve billion, twelve million, two hundred twenty-two thousand, one hundred thirteen".
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