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1123409993 is a prime number
BaseRepresentation
bin100001011110101…
…1110000001001001
32220021220010210112
41002331132001021
54300043104433
6303250324105
736560553536
oct10275360111
92807803715
101123409993
11527154612
12274289635
1314b989254
14a92b3d8d
156895c348
hex42f5e049

1123409993 has 2 divisors, whose sum is σ = 1123409994. Its totient is φ = 1123409992.

The previous prime is 1123409983. The next prime is 1123410049. The reversal of 1123409993 is 3999043211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 853399369 + 270010624 = 29213^2 + 16432^2 .

It is an emirp because it is prime and its reverse (3999043211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1123409993 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1123409993.

It is not a weakly prime, because it can be changed into another prime (1123409983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561704996 + 561704997.

It is an arithmetic number, because the mean of its divisors is an integer number (561704997).

Almost surely, 21123409993 is an apocalyptic number.

It is an amenable number.

1123409993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123409993 is an equidigital number, since it uses as much as digits as its factorization.

1123409993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52488, while the sum is 41.

The square root of 1123409993 is about 33517.3088567683. The cubic root of 1123409993 is about 1039.5517030520.

The spelling of 1123409993 in words is "one billion, one hundred twenty-three million, four hundred nine thousand, nine hundred ninety-three".