Base | Representation |
---|---|
bin | 1010001101111010011011… |
… | …1111000100011001101101 |
3 | 1110202222021121022101102022 |
4 | 2203132212333010121231 |
5 | 2433030010100424442 |
6 | 35520520530235525 |
7 | 2236432326123044 |
oct | 243364677043155 |
9 | 43688247271368 |
10 | 11234141029997 |
11 | 3641410813286 |
12 | 1315303125ba5 |
13 | 6364b4a07b12 |
14 | 2aba41a4755b |
15 | 14735c0893d2 |
hex | a37a6fc466d |
11234141029997 has 2 divisors, whose sum is σ = 11234141029998. Its totient is φ = 11234141029996.
The previous prime is 11234141029987. The next prime is 11234141030029. The reversal of 11234141029997 is 79992014143211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10033569391561 + 1200571638436 = 3167581^2 + 1095706^2 .
It is a cyclic number.
It is not a de Polignac number, because 11234141029997 - 242 = 6836094518893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11234141029987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617070514998 + 5617070514999.
It is an arithmetic number, because the mean of its divisors is an integer number (5617070514999).
Almost surely, 211234141029997 is an apocalyptic number.
It is an amenable number.
11234141029997 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234141029997 is an equidigital number, since it uses as much as digits as its factorization.
11234141029997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 979776, while the sum is 53.
The spelling of 11234141029997 in words is "eleven trillion, two hundred thirty-four billion, one hundred forty-one million, twenty-nine thousand, nine hundred ninety-seven".
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