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112997494853 is a prime number
BaseRepresentation
bin110100100111100101…
…1001111000001000101
3101210122222201111021222
41221033023033001011
53322404324313403
6123524344250125
711110116600335
oct1511713170105
9353588644258
10112997494853
1143a1615a391
1219a96770945
13a86a5150b9
14567d3370c5
152e15344338
hex1a4f2cf045

112997494853 has 2 divisors, whose sum is σ = 112997494854. Its totient is φ = 112997494852.

The previous prime is 112997494829. The next prime is 112997494873. The reversal of 112997494853 is 358494799211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112263193249 + 734301604 = 335057^2 + 27098^2 .

It is a cyclic number.

It is not a de Polignac number, because 112997494853 - 214 = 112997478469 is a prime.

It is a super-2 number, since 2×1129974948532 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112997494823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56498747426 + 56498747427.

It is an arithmetic number, because the mean of its divisors is an integer number (56498747427).

Almost surely, 2112997494853 is an apocalyptic number.

It is an amenable number.

112997494853 is a deficient number, since it is larger than the sum of its proper divisors (1).

112997494853 is an equidigital number, since it uses as much as digits as its factorization.

112997494853 is an evil number, because the sum of its binary digits is even.

The product of its digits is 19595520, while the sum is 62.

The spelling of 112997494853 in words is "one hundred twelve billion, nine hundred ninety-seven million, four hundred ninety-four thousand, eight hundred fifty-three".