11310130112033 has 4 divisors (see below), whose sum is σ = 11310369592980. Its totient is φ = 11309890631088.

The previous prime is 11310130111999. The next prime is 11310130112053. The reversal of 11310130112033 is 33021103101311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3401250685504 + 7908879426529 = 1844248^2 + 2812273^2 .

It is a cyclic number.

It is not a de Polignac number, because 11310130112033 - 2²⁸ = 11309861676577 is a prime.

It is a super-2 number, since 2×11310130112033² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11310130111996 and 11310130112014.

It is not an unprimeable number, because it can be changed into a prime (11310130112053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119669618 + ... + 119764091.

It is an arithmetic number, because the mean of its divisors is an integer number (2827592398245).

Almost surely, 2^{11310130112033} is an apocalyptic number.

It is an amenable number.

11310130112033 is a deficient number, since it is larger than the sum of its proper divisors (239480947).

11310130112033 is an equidigital number, since it uses as much as digits as its factorization.

11310130112033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239480946.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 11310130112033 its reverse (33021103101311), we get a palindrome (44331233213344).

The spelling of 11310130112033 in words is "eleven trillion, three hundred ten billion, one hundred thirty million, one hundred twelve thousand, thirty-three".