Base | Representation |
---|---|
bin | 1010010010011001111010… |
… | …1100010010110101110000 |
3 | 1111001100110201210101100122 |
4 | 2210212132230102311300 |
5 | 2440311031143131000 |
6 | 40020202241105412 |
7 | 2245133560452563 |
oct | 244463654226560 |
9 | 44040421711318 |
10 | 11311311302000 |
11 | 3671111387886 |
12 | 132825b328268 |
13 | 640862804468 |
14 | 2b1682a604da |
15 | 149376dea085 |
hex | a499eb12d70 |
11311311302000 has 40 divisors (see below), whose sum is σ = 27350750733072. Its totient is φ = 4524524520000.
The previous prime is 11311311301981. The next prime is 11311311302047. The reversal of 11311311302000 is 20311311311.
It is a tau number, because it is divible by the number of its divisors (40).
It is a self number, because there is not a number n which added to its sum of digits gives 11311311302000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2827825826 + ... + 2827829825.
Almost surely, 211311311302000 is an apocalyptic number.
11311311302000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11311311302000 is an abundant number, since it is smaller than the sum of its proper divisors (16039439431072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11311311302000 is an equidigital number, since it uses as much as digits as its factorization.
11311311302000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5655655674 (or 5655655658 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11311311302000 its reverse (20311311311), we get a palindrome (11331622613311).
The spelling of 11311311302000 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred two thousand".
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