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1131202002331 is a prime number
BaseRepresentation
bin10000011101100000111…
…001001011110110011011
311000010211102010201022201
4100131200321023312123
5122013200203033311
62223400024431031
7144504145241242
oct20354071136633
94003742121281
101131202002331
113a6816049185
12163299318477
13828971b604b
143ca71403959
151e659dad9c1
hex10760e4bd9b

1131202002331 has 2 divisors, whose sum is σ = 1131202002332. Its totient is φ = 1131202002330.

The previous prime is 1131202002317. The next prime is 1131202002349. The reversal of 1131202002331 is 1332002021311.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131202002331 is a prime.

It is a super-2 number, since 2×11312020023312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1131202002299 and 1131202002308.

It is not a weakly prime, because it can be changed into another prime (1131202402331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565601001165 + 565601001166.

It is an arithmetic number, because the mean of its divisors is an integer number (565601001166).

Almost surely, 21131202002331 is an apocalyptic number.

1131202002331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131202002331 is an equidigital number, since it uses as much as digits as its factorization.

1131202002331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1131202002331 its reverse (1332002021311), we get a palindrome (2463204023642).

The spelling of 1131202002331 in words is "one trillion, one hundred thirty-one billion, two hundred two million, two thousand, three hundred thirty-one".