Base | Representation |
---|---|
bin | 10000011101100000111… |
… | …001001011110110011011 |
3 | 11000010211102010201022201 |
4 | 100131200321023312123 |
5 | 122013200203033311 |
6 | 2223400024431031 |
7 | 144504145241242 |
oct | 20354071136633 |
9 | 4003742121281 |
10 | 1131202002331 |
11 | 3a6816049185 |
12 | 163299318477 |
13 | 828971b604b |
14 | 3ca71403959 |
15 | 1e659dad9c1 |
hex | 10760e4bd9b |
1131202002331 has 2 divisors, whose sum is σ = 1131202002332. Its totient is φ = 1131202002330.
The previous prime is 1131202002317. The next prime is 1131202002349. The reversal of 1131202002331 is 1332002021311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131202002331 is a prime.
It is a super-2 number, since 2×11312020023312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131202002299 and 1131202002308.
It is not a weakly prime, because it can be changed into another prime (1131202402331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565601001165 + 565601001166.
It is an arithmetic number, because the mean of its divisors is an integer number (565601001166).
Almost surely, 21131202002331 is an apocalyptic number.
1131202002331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131202002331 is an equidigital number, since it uses as much as digits as its factorization.
1131202002331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1131202002331 its reverse (1332002021311), we get a palindrome (2463204023642).
The spelling of 1131202002331 in words is "one trillion, one hundred thirty-one billion, two hundred two million, two thousand, three hundred thirty-one".
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