11312301201233 has 4 divisors (see below), whose sum is σ = 11312309006448. Its totient is φ = 11312293396020.

The previous prime is 11312301201209. The next prime is 11312301201251. The reversal of 11312301201233 is 33210210321311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11312301201233 - 2⁴⁰ = 10212789573457 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312301201199 and 11312301201208.

It is not an unprimeable number, because it can be changed into a prime (11312301201283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1017803 + ... + 4864208.

It is an arithmetic number, because the mean of its divisors is an integer number (2828077251612).

Almost surely, 2^{11312301201233} is an apocalyptic number.

It is an amenable number.

11312301201233 is a deficient number, since it is larger than the sum of its proper divisors (7805215).

11312301201233 is an equidigital number, since it uses as much as digits as its factorization.

11312301201233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7805214.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11312301201233 its reverse (33210210321311), we get a palindrome (44522511522544).

The spelling of 11312301201233 in words is "eleven trillion, three hundred twelve billion, three hundred one million, two hundred one thousand, two hundred thirty-three".