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11312433 = 331141929
BaseRepresentation
bin101011001001…
…110100110001
3210021201202000
4223021310301
510343444213
61042244213
7165103566
oct53116461
923251660
1011312433
116427220
123956669
132461062
14170686d
15ed6c73
hexac9d31

11312433 has 32 divisors (see below), whose sum is σ = 18748800. Its totient is φ = 6681600.

The previous prime is 11312393. The next prime is 11312443. The reversal of 11312433 is 33421311.

11312433 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11312433 - 28 = 11312177 is a prime.

It is a super-2 number, since 2×113124332 = 255942280758978, which contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11312443) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11713 + ... + 12641.

It is an arithmetic number, because the mean of its divisors is an integer number (585900).

Almost surely, 211312433 is an apocalyptic number.

It is an amenable number.

11312433 is a deficient number, since it is larger than the sum of its proper divisors (7436367).

11312433 is a wasteful number, since it uses less digits than its factorization.

11312433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 990 (or 984 counting only the distinct ones).

The product of its digits is 216, while the sum is 18.

The square root of 11312433 is about 3363.3960516121. The cubic root of 11312433 is about 224.4839729764.

Adding to 11312433 its reverse (33421311), we get a palindrome (44733744).

The spelling of 11312433 in words is "eleven million, three hundred twelve thousand, four hundred thirty-three".

Divisors: 1 3 9 11 27 33 41 99 123 297 369 451 929 1107 1353 2787 4059 8361 10219 12177 25083 30657 38089 91971 114267 275913 342801 418979 1028403 1256937 3770811 11312433