Base | Representation |
---|---|
bin | 110100101101101010… |
… | …0000000001111001011 |
3 | 101211012011212201202121 |
4 | 1221123110000033023 |
5 | 3323313441321303 |
6 | 124000500512111 |
7 | 11115141434263 |
oct | 1513324001713 |
9 | 354164781677 |
10 | 113201120203 |
11 | 440100990a6 |
12 | 19b329ab637 |
13 | a8a076b582 |
14 | 569c3c07a3 |
15 | 2e281679bd |
hex | 1a5b5003cb |
113201120203 has 2 divisors, whose sum is σ = 113201120204. Its totient is φ = 113201120202.
The previous prime is 113201120177. The next prime is 113201120239. The reversal of 113201120203 is 302021102311.
It is a weak prime.
It is an emirp because it is prime and its reverse (302021102311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113201120203 - 233 = 104611185611 is a prime.
It is a super-2 number, since 2×1132011202032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113201120003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600560101 + 56600560102.
It is an arithmetic number, because the mean of its divisors is an integer number (56600560102).
Almost surely, 2113201120203 is an apocalyptic number.
113201120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
113201120203 is an equidigital number, since it uses as much as digits as its factorization.
113201120203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 113201120203 its reverse (302021102311), we get a palindrome (415222222514).
The spelling of 113201120203 in words is "one hundred thirteen billion, two hundred one million, one hundred twenty thousand, two hundred three".
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