Base | Representation |
---|---|
bin | 1010010011100000110001… |
… | …0111100001100010011000 |
3 | 1111010011120021010100000111 |
4 | 2210320030113201202120 |
5 | 2441114004243020440 |
6 | 40033025440014104 |
7 | 2246406112214113 |
oct | 244701427414230 |
9 | 44104507110014 |
10 | 11330331220120 |
11 | 3679191657880 |
12 | 132ba89001334 |
13 | 6425a4126c93 |
14 | 2b2568b0157a |
15 | 149adbabb4ea |
hex | a4e0c5e1898 |
11330331220120 has 64 divisors (see below), whose sum is σ = 27823977044640. Its totient is φ = 4118170214400.
The previous prime is 11330331220067. The next prime is 11330331220133. The reversal of 11330331220120 is 2102213303311.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 11330331220091 and 11330331220100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5163691 + ... + 7023130.
Almost surely, 211330331220120 is an apocalyptic number.
11330331220120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11330331220120 is an abundant number, since it is smaller than the sum of its proper divisors (16493645824520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11330331220120 is a wasteful number, since it uses less digits than its factorization.
11330331220120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12188956 (or 12188952 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11330331220120 its reverse (2102213303311), we get a palindrome (13432544523431).
The spelling of 11330331220120 in words is "eleven trillion, three hundred thirty billion, three hundred thirty-one million, two hundred twenty thousand, one hundred twenty".
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