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11331023000119 is a prime number
BaseRepresentation
bin1010010011100011010110…
…0110011101001000110111
31111010020100110211101202221
42210320311212131020313
52441121413342000434
640033222231143211
72246432212231324
oct244706546351067
944106313741687
1011331023000119
1136795070a2389
121330040814b07
13642684548a64
142b25d2939b4b
15149b2c6b82b4
hexa4e3599d237

11331023000119 has 2 divisors, whose sum is σ = 11331023000120. Its totient is φ = 11331023000118.

The previous prime is 11331023000113. The next prime is 11331023000161. The reversal of 11331023000119 is 91100032013311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11331023000119 - 29 = 11331022999607 is a prime.

It is a super-2 number, since 2×113310230001192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331023000093 and 11331023000102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331023000113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665511500059 + 5665511500060.

It is an arithmetic number, because the mean of its divisors is an integer number (5665511500060).

Almost surely, 211331023000119 is an apocalyptic number.

11331023000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331023000119 is an equidigital number, since it uses as much as digits as its factorization.

11331023000119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 11331023000119 in words is "eleven trillion, three hundred thirty-one billion, twenty-three million, one hundred nineteen", and thus it is an aban number.