Base | Representation |
---|---|
bin | 1010010011100011101011… |
… | …0011100110001101010111 |
3 | 1111010020120120011021112021 |
4 | 2210320322303212031113 |
5 | 2441122103221044343 |
6 | 40033235031034011 |
7 | 2246434322440054 |
oct | 244707263461527 |
9 | 44106516137467 |
10 | 11331110331223 |
11 | 3679551420551 |
12 | 1330065b0b907 |
13 | 642699674c77 |
14 | 2b260039002b |
15 | 149b351b90ed |
hex | a4e3ace6357 |
11331110331223 has 4 divisors (see below), whose sum is σ = 11467629732888. Its totient is φ = 11194590929560.
The previous prime is 11331110331197. The next prime is 11331110331239. The reversal of 11331110331223 is 32213301113311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11331110331223 - 29 = 11331110330711 is a prime.
It is a super-2 number, since 2×113311103312232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331110331283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68259700708 + ... + 68259700873.
It is an arithmetic number, because the mean of its divisors is an integer number (2866907433222).
Almost surely, 211331110331223 is an apocalyptic number.
11331110331223 is a deficient number, since it is larger than the sum of its proper divisors (136519401665).
11331110331223 is an equidigital number, since it uses as much as digits as its factorization.
11331110331223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136519401664.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 11331110331223 its reverse (32213301113311), we get a palindrome (43544411444534).
The spelling of 11331110331223 in words is "eleven trillion, three hundred thirty-one billion, one hundred ten million, three hundred thirty-one thousand, two hundred twenty-three".
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