Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0000100010100111111111 |
3 | 1111010020121101022212010020 |
4 | 2210320323200202213333 |
5 | 2441122114230104043 |
6 | 40033240131343223 |
7 | 2246434524540246 |
oct | 244707340424777 |
9 | 44106541285106 |
10 | 11331122113023 |
11 | 3679558038379 |
12 | 1330069a51b13 |
13 | 64269bc3b84b |
14 | 2b2601b7995d |
15 | 149b36244e83 |
hex | a4e3b8229ff |
11331122113023 has 4 divisors (see below), whose sum is σ = 15108162817368. Its totient is φ = 7554081408680.
The previous prime is 11331122113009. The next prime is 11331122113027. The reversal of 11331122113023 is 32031122113311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11331122113023 - 237 = 11193683159551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331122112984 and 11331122113002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331122113027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888520352168 + ... + 1888520352173.
It is an arithmetic number, because the mean of its divisors is an integer number (3777040704342).
Almost surely, 211331122113023 is an apocalyptic number.
11331122113023 is a deficient number, since it is larger than the sum of its proper divisors (3777040704345).
11331122113023 is an equidigital number, since it uses as much as digits as its factorization.
11331122113023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3777040704344.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 11331122113023 its reverse (32031122113311), we get a palindrome (43362244226334).
The spelling of 11331122113023 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, one hundred thirteen thousand, twenty-three".
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