Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0010111001111010010100 |
3 | 1111010020122000021112011010 |
4 | 2210320330002321322110 |
5 | 2441122124031340200 |
6 | 40033241052412220 |
7 | 2246434664236404 |
oct | 244707402717224 |
9 | 44106560245133 |
10 | 11331131121300 |
11 | 3679562130431 |
12 | 1330070a77070 |
13 | 6426a0a73ba3 |
14 | 2b2603042804 |
15 | 149b36e24150 |
hex | a4e3c0b9e94 |
11331131121300 has 36 divisors (see below), whose sum is σ = 32784739378496. Its totient is φ = 3021634965600.
The previous prime is 11331131121227. The next prime is 11331131121329. The reversal of 11331131121300 is 312113113311.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 18885218236 + ... + 18885218835.
Almost surely, 211331131121300 is an apocalyptic number.
11331131121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11331131121300 is an abundant number, since it is smaller than the sum of its proper divisors (21453608257196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331131121300 is a wasteful number, since it uses less digits than its factorization.
11331131121300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37770437088 (or 37770437081 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 11331131121300 its reverse (312113113311), we get a palindrome (11643244234611).
The spelling of 11331131121300 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred twenty-one thousand, three hundred".
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