Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101010101111010111 |
3 | 1111010020122000122200111122 |
4 | 2210320330003222233113 |
5 | 2441122124104240203 |
6 | 40033241100554155 |
7 | 2246434666031453 |
oct | 244707403525727 |
9 | 44106560580448 |
10 | 11331131321303 |
11 | 3679562257722 |
12 | 1330070b5295b |
13 | 6426a0b13c31 |
14 | 2b2603095663 |
15 | 149b36e63538 |
hex | a4e3c0eabd7 |
11331131321303 has 2 divisors, whose sum is σ = 11331131321304. Its totient is φ = 11331131321302.
The previous prime is 11331131321273. The next prime is 11331131321359. The reversal of 11331131321303 is 30312313113311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331131321303 - 232 = 11326836354007 is a prime.
It is a super-2 number, since 2×113311313213032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331131320303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565660651 + 5665565660652.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565660652).
Almost surely, 211331131321303 is an apocalyptic number.
11331131321303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131321303 is an equidigital number, since it uses as much as digits as its factorization.
11331131321303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 11331131321303 its reverse (30312313113311), we get a palindrome (41643444434614).
The spelling of 11331131321303 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred twenty-one thousand, three hundred three".
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