Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101101101000001001 |
3 | 1111010020122000200021201122 |
4 | 2210320330003231220021 |
5 | 2441122124110130004 |
6 | 40033241101125025 |
7 | 2246434666111106 |
oct | 244707403555011 |
9 | 44106560607648 |
10 | 11331131333129 |
11 | 36795622655a3 |
12 | 1330070b59775 |
13 | 6426a0b1942a |
14 | 2b2603099aad |
15 | 149b36e66cbe |
hex | a4e3c0eda09 |
11331131333129 has 2 divisors, whose sum is σ = 11331131333130. Its totient is φ = 11331131333128.
The previous prime is 11331131333069. The next prime is 11331131333141. The reversal of 11331131333129 is 92133313113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9574989545104 + 1756141788025 = 3094348^2 + 1325195^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331131333129 - 216 = 11331131267593 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11331131333329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565666564 + 5665565666565.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565666565).
Almost surely, 211331131333129 is an apocalyptic number.
It is an amenable number.
11331131333129 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131333129 is an equidigital number, since it uses as much as digits as its factorization.
11331131333129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13122, while the sum is 35.
The spelling of 11331131333129 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred thirty-three thousand, one hundred twenty-nine".
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