Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101101101000100001 |
3 | 1111010020122000200021202112 |
4 | 2210320330003231220201 |
5 | 2441122124110130103 |
6 | 40033241101125105 |
7 | 2246434666111142 |
oct | 244707403555041 |
9 | 44106560607675 |
10 | 11331131333153 |
11 | 3679562265615 |
12 | 1330070b59795 |
13 | 6426a0b19448 |
14 | 2b2603099ac9 |
15 | 149b36e66cd8 |
hex | a4e3c0eda21 |
11331131333153 has 2 divisors, whose sum is σ = 11331131333154. Its totient is φ = 11331131333152.
The previous prime is 11331131333141. The next prime is 11331131333167. The reversal of 11331131333153 is 35133313113311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10780794361744 + 550336971409 = 3283412^2 + 741847^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331131333153 - 226 = 11331064224289 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331131332153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565666576 + 5665565666577.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565666577).
Almost surely, 211331131333153 is an apocalyptic number.
It is an amenable number.
11331131333153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131333153 is an equidigital number, since it uses as much as digits as its factorization.
11331131333153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10935, while the sum is 32.
Adding to 11331131333153 its reverse (35133313113311), we get a palindrome (46464444446464).
The spelling of 11331131333153 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred thirty-three thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •