113333002112131 has 2 divisors, whose sum is σ = 113333002112132. Its totient is φ = 113333002112130.

The previous prime is 113333002112117. The next prime is 113333002112167. The reversal of 113333002112131 is 131211200333311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113333002112131 - 2⁴³ = 104536909089923 is a prime.

It is a super-3 number, since 3×113333002112131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 113333002112096 and 113333002112105.

It is not a weakly prime, because it can be changed into another prime (113333002112111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56666501056065 + 56666501056066.

It is an arithmetic number, because the mean of its divisors is an integer number (56666501056066).

Almost surely, 2^{113333002112131} is an apocalyptic number.

113333002112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113333002112131 is an equidigital number, since it uses as much as digits as its factorization.

113333002112131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 113333002112131 its reverse (131211200333311), we get a palindrome (244544202445442).

The spelling of 113333002112131 in words is "one hundred thirteen trillion, three hundred thirty-three billion, two million, one hundred twelve thousand, one hundred thirty-one".