Base | Representation |
---|---|
bin | 11001110100011001111101… |
… | …101101000111100111110001 |
3 | 112220001111201210010220112020 |
4 | 121310121331231013213301 |
5 | 104340420411303220340 |
6 | 1041301135525222053 |
7 | 32626615450342332 |
oct | 3164317555074761 |
9 | 486044653126466 |
10 | 113552454351345 |
11 | 331aa3641a1959 |
12 | 1089b287261929 |
13 | 4b48c48327639 |
14 | 2007d7a718289 |
15 | d1db5eb3e9d0 |
hex | 67467db479f1 |
113552454351345 has 8 divisors (see below), whose sum is σ = 181683926962176. Its totient is φ = 60561308987376.
The previous prime is 113552454351317. The next prime is 113552454351461. The reversal of 113552454351345 is 543153454255311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 113552454351345 - 214 = 113552454334961 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3785081811697 + ... + 3785081811726.
It is an arithmetic number, because the mean of its divisors is an integer number (22710490870272).
Almost surely, 2113552454351345 is an apocalyptic number.
113552454351345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113552454351345 is a deficient number, since it is larger than the sum of its proper divisors (68131472610831).
113552454351345 is an equidigital number, since it uses as much as digits as its factorization.
113552454351345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7570163623431.
The product of its digits is 10800000, while the sum is 51.
The spelling of 113552454351345 in words is "one hundred thirteen trillion, five hundred fifty-two billion, four hundred fifty-four million, three hundred fifty-one thousand, three hundred forty-five".
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