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113553532314113 = 1731215471598319
BaseRepresentation
bin11001110100011010111101…
…111101001110001000000001
3112220001121111220112002110012
4121310122331331032020001
5104340430113233022423
61041301434513514305
732626654250023043
oct3164327575161001
9486047456462405
10113553532314113
11331aa867725281
121089b528272995
134b4908a760828
14200803d95ba93
15d1dbc45c1078
hex6746bdf4e201

113553532314113 has 8 divisors (see below), whose sum is σ = 124111640632320. Its totient is φ = 103426367192640.

The previous prime is 113553532314083. The next prime is 113553532314119. The reversal of 113553532314113 is 311413235355311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113553532314113 - 232 = 113549237346817 is a prime.

It is not an unprimeable number, because it can be changed into a prime (113553532314119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 107735798633 + ... + 107735799686.

It is an arithmetic number, because the mean of its divisors is an integer number (15513955079040).

Almost surely, 2113553532314113 is an apocalyptic number.

It is an amenable number.

113553532314113 is a deficient number, since it is larger than the sum of its proper divisors (10558108318207).

113553532314113 is a wasteful number, since it uses less digits than its factorization.

113553532314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215471598367.

The product of its digits is 243000, while the sum is 41.

Adding to 113553532314113 its reverse (311413235355311), we get a palindrome (424966767669424).

The spelling of 113553532314113 in words is "one hundred thirteen trillion, five hundred fifty-three billion, five hundred thirty-two million, three hundred fourteen thousand, one hundred thirteen".

Divisors: 1 17 31 527 215471598319 3663017171423 6679619547889 113553532314113