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1139320187 = 2939286903
BaseRepresentation
bin100001111101000…
…1010010101111011
32221101211110110222
41003322022111323
54313131221222
6305015330255
740143030125
oct10372122573
92841743428
101139320187
11535131135
1227968098b
13152069c75
14ab456215
156a051542
hex43e8a57b

1139320187 has 4 divisors (see below), whose sum is σ = 1178607120. Its totient is φ = 1100033256.

The previous prime is 1139320159. The next prime is 1139320207. The reversal of 1139320187 is 7810239311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1139320187 - 210 = 1139319163 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1139320487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19643423 + ... + 19643480.

It is an arithmetic number, because the mean of its divisors is an integer number (294651780).

Almost surely, 21139320187 is an apocalyptic number.

1139320187 is a deficient number, since it is larger than the sum of its proper divisors (39286933).

1139320187 is an equidigital number, since it uses as much as digits as its factorization.

1139320187 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39286932.

The product of its (nonzero) digits is 9072, while the sum is 35.

The square root of 1139320187 is about 33753.8173692991. The cubic root of 1139320187 is about 1044.4362356727.

Adding to 1139320187 its reverse (7810239311), we get a palindrome (8949559498).

The spelling of 1139320187 in words is "one billion, one hundred thirty-nine million, three hundred twenty thousand, one hundred eighty-seven".

Divisors: 1 29 39286903 1139320187