1140113 has 4 divisors (see below), whose sum is σ = 1227828. Its totient is φ = 1052400.

The previous prime is 1140103. The next prime is 1140121. The reversal of 1140113 is 3110411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3110411 = 53 ⋅58687.

It can be written as a sum of positive squares in 2 ways, for example, as 693889 + 446224 = 833^2 + 668^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140113 - 2¹⁴ = 1123729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1140094 and 1140103.

It is not an unprimeable number, because it can be changed into a prime (1140103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43838 + ... + 43863.

It is an arithmetic number, because the mean of its divisors is an integer number (306957).

2^1140113 is an apocalyptic number.

1140113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1140113 is a deficient number, since it is larger than the sum of its proper divisors (87715).

1140113 is an equidigital number, since it uses as much as digits as its factorization.

1140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87714.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1140113 is about 1067.7607409902. The cubic root of 1140113 is about 104.4678441695.

Adding to 1140113 its reverse (3110411), we get a palindrome (4250524).

The spelling of 1140113 in words is "one million, one hundred forty thousand, one hundred thirteen".