Base | Representation |
---|---|
bin | 110101000110001100… |
… | …0101110011001011001 |
3 | 101220022120002210011111 |
4 | 1222030120232121121 |
5 | 3332010224111213 |
6 | 124214311300321 |
7 | 11144426521600 |
oct | 1521430563131 |
9 | 356276083144 |
10 | 114024441433 |
11 | 443a2908571 |
12 | 1a12267a6a1 |
13 | a9a21c84b6 |
14 | 573989aa37 |
15 | 2e75599a3d |
hex | 1a8c62e659 |
114024441433 has 12 divisors (see below), whose sum is σ = 134238762000. Its totient is φ = 96557699112.
The previous prime is 114024441413. The next prime is 114024441449. The reversal of 114024441433 is 334144420411.
It is not a de Polignac number, because 114024441433 - 233 = 105434506841 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114024441395 and 114024441404.
It is not an unprimeable number, because it can be changed into a prime (114024441403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14014183 + ... + 14022316.
It is an arithmetic number, because the mean of its divisors is an integer number (11186563500).
Almost surely, 2114024441433 is an apocalyptic number.
It is an amenable number.
114024441433 is a deficient number, since it is larger than the sum of its proper divisors (20214320567).
114024441433 is an equidigital number, since it uses as much as digits as its factorization.
114024441433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28036596 (or 28036589 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 114024441433 its reverse (334144420411), we get a palindrome (448168861844).
The spelling of 114024441433 in words is "one hundred fourteen billion, twenty-four million, four hundred forty-one thousand, four hundred thirty-three".
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