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114024441433 = 728328036499
BaseRepresentation
bin110101000110001100…
…0101110011001011001
3101220022120002210011111
41222030120232121121
53332010224111213
6124214311300321
711144426521600
oct1521430563131
9356276083144
10114024441433
11443a2908571
121a12267a6a1
13a9a21c84b6
14573989aa37
152e75599a3d
hex1a8c62e659

114024441433 has 12 divisors (see below), whose sum is σ = 134238762000. Its totient is φ = 96557699112.

The previous prime is 114024441413. The next prime is 114024441449. The reversal of 114024441433 is 334144420411.

It is not a de Polignac number, because 114024441433 - 233 = 105434506841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114024441395 and 114024441404.

It is not an unprimeable number, because it can be changed into a prime (114024441403) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14014183 + ... + 14022316.

It is an arithmetic number, because the mean of its divisors is an integer number (11186563500).

Almost surely, 2114024441433 is an apocalyptic number.

It is an amenable number.

114024441433 is a deficient number, since it is larger than the sum of its proper divisors (20214320567).

114024441433 is an equidigital number, since it uses as much as digits as its factorization.

114024441433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28036596 (or 28036589 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 114024441433 its reverse (334144420411), we get a palindrome (448168861844).

The spelling of 114024441433 in words is "one hundred fourteen billion, twenty-four million, four hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 7 49 83 581 4067 28036499 196255493 1373788451 2327029417 16289205919 114024441433