1141321443113 has 4 divisors (see below), whose sum is σ = 1157396393088. Its totient is φ = 1125246493140.

The previous prime is 1141321443079. The next prime is 1141321443121. The reversal of 1141321443113 is 3113441231411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1141321443113 - 2²² = 1141317248809 is a prime.

It is a super-2 number, since 2×1141321443113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1141321446113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8037474881 + ... + 8037475022.

It is an arithmetic number, because the mean of its divisors is an integer number (289349098272).

Almost surely, 2^{1141321443113} is an apocalyptic number.

It is an amenable number.

1141321443113 is a deficient number, since it is larger than the sum of its proper divisors (16074949975).

1141321443113 is an equidigital number, since it uses as much as digits as its factorization.

1141321443113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16074949974.

The product of its digits is 3456, while the sum is 29.

Adding to 1141321443113 its reverse (3113441231411), we get a palindrome (4254762674524).

The spelling of 1141321443113 in words is "one trillion, one hundred forty-one billion, three hundred twenty-one million, four hundred forty-three thousand, one hundred thirteen".