Base | Representation |
---|---|
bin | 11001111110001001100100… |
… | …011000000111001111010111 |
3 | 112222102112001122210021101110 |
4 | 121332021210120013033113 |
5 | 104432403221321000120 |
6 | 1042532514402030103 |
7 | 33026161511164515 |
oct | 3176114430071727 |
9 | 488375048707343 |
10 | 114222044312535 |
11 | 3343832a285275 |
12 | 10988bb7648333 |
13 | 4b97128484773 |
14 | 202c53ad594b5 |
15 | d3129e0c52e0 |
hex | 67e2646073d7 |
114222044312535 has 16 divisors (see below), whose sum is σ = 192373969368960. Its totient is φ = 57712190810400.
The previous prime is 114222044312477. The next prime is 114222044312591. The reversal of 114222044312535 is 535213440222411.
It is not a de Polignac number, because 114222044312535 - 27 = 114222044312407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114222044312493 and 114222044312502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 200389551141 + ... + 200389551710.
It is an arithmetic number, because the mean of its divisors is an integer number (12023373085560).
Almost surely, 2114222044312535 is an apocalyptic number.
114222044312535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114222044312535 is a deficient number, since it is larger than the sum of its proper divisors (78151925056425).
114222044312535 is a wasteful number, since it uses less digits than its factorization.
114222044312535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 400779102878.
The product of its (nonzero) digits is 230400, while the sum is 39.
Adding to 114222044312535 its reverse (535213440222411), we get a palindrome (649435484534946).
The spelling of 114222044312535 in words is "one hundred fourteen trillion, two hundred twenty-two billion, forty-four million, three hundred twelve thousand, five hundred thirty-five".
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